4(x+3)-4=8(1^2x+1

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Solution for 4(x+3)-4=8(1^2x+1 equation: 



4(x+3)-4=8(1^2x+1

We move all terms to the left:

4(x+3)-4-(8(1^2x+1)=0

We multiply parentheses

4x-(8(1^2x+1)-4+12=0

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